ProofObjectsThe Curry-Howard Correspondence
Set Warnings "-notation-overridden,-parsing".
From LF Require Export IndProp.
From LF Require Export IndProp.
"Algorithms are the computational content of proofs."  —Robert Harper
 
Print ev.
(* ==>
Inductive ev : nat -> Prop :=
| ev_0 : ev 0
| ev_SS : forall n, ev n -> ev (S (S n)).
*)
(* ==>
Inductive ev : nat -> Prop :=
| ev_0 : ev 0
| ev_SS : forall n, ev n -> ev (S (S n)).
*)
Suppose we introduce an alternative pronunciation of ":".
    Instead of "has type," we can say "is a proof of."  For example,
    the second line in the definition of ev declares that ev_0 : ev
    0.  Instead of "ev_0 has type ev 0," we can say that "ev_0
    is a proof of ev 0." 
 
 This pun between types and propositions — between : as "has type"
    and : as "is a proof of" or "is evidence for" — is called the
    Curry-Howard correspondence.  It proposes a deep connection
    between the world of logic and the world of computation:
 
 Many useful insights follow from this connection.  To begin with,
    it gives us a natural interpretation of the type of the ev_SS
    constructor: 
                 propositions  ~  types
                 proofs        ~  data values
    See [Wadler 2015] for a brief history and up-to-date exposition. 
Check ev_SS.
(* ===> ev_SS : forall n,
ev n ->
ev (S (S n)) *)
(* ===> ev_SS : forall n,
ev n ->
ev (S (S n)) *)
This can be read "ev_SS is a constructor that takes two
    arguments — a number n and evidence for the proposition ev
    n — and yields evidence for the proposition ev (S (S n))." 
 
 Now let's look again at a previous proof involving ev. 
Theorem ev_4 : ev 4.
Proof.
apply ev_SS. apply ev_SS. apply ev_0. Qed.
Proof.
apply ev_SS. apply ev_SS. apply ev_0. Qed.
As with ordinary data values and functions, we can use the Print
    command to see the proof object that results from this proof
    script. 
Print ev_4.
(* ===> ev_4 = ev_SS 2 (ev_SS 0 ev_0)
: ev 4 *)
(* ===> ev_4 = ev_SS 2 (ev_SS 0 ev_0)
: ev 4 *)
Indeed, we can also write down this proof object directly,
    without the need for a separate proof script: 
Check (ev_SS 2 (ev_SS 0 ev_0)).
(* ===> ev 4 *)
(* ===> ev 4 *)
The expression ev_SS 2 (ev_SS 0 ev_0) can be thought of as
    instantiating the parameterized constructor ev_SS with the
    specific arguments 2 and 0 plus the corresponding proof
    objects for its premises ev 2 and ev 0.  Alternatively, we can
    think of ev_SS as a primitive "evidence constructor" that, when
    applied to a particular number, wants to be further applied to
    evidence that that number is even; its type,
 
 
 We saw in the Logic chapter that we can use function
    application syntax to instantiate universally quantified variables
    in lemmas, as well as to supply evidence for assumptions that
    these lemmas impose.  For instance: 
      ∀ n, ev n → ev (S (S n)),
 
    expresses this functionality, in the same way that the polymorphic
    type ∀X, list X expresses the fact that the constructor
    nil can be thought of as a function from types to empty lists
    with elements of that type. 
Theorem ev_4': ev 4.
Proof.
apply (ev_SS 2 (ev_SS 0 ev_0)).
Qed.
Proof.
apply (ev_SS 2 (ev_SS 0 ev_0)).
Qed.
Proof Scripts
Theorem ev_4'' : ev 4.
Proof.
Show Proof.
apply ev_SS.
Show Proof.
apply ev_SS.
Show Proof.
apply ev_0.
Show Proof.
Qed.
Proof.
Show Proof.
apply ev_SS.
Show Proof.
apply ev_SS.
Show Proof.
apply ev_0.
Show Proof.
Qed.
At any given moment, Coq has constructed a term with a
    "hole" (indicated by ?Goal here, and so on), and it knows what
    type of evidence is needed to fill this hole. 
 
    Each hole corresponds to a subgoal, and the proof is
    finished when there are no more subgoals.  At this point, the
    evidence we've built stored in the global context under the name
    given in the Theorem command. 
 
 Tactic proofs are useful and convenient, but they are not
    essential: in principle, we can always construct the required
    evidence by hand, as shown above. Then we can use Definition
    (rather than Theorem) to give a global name directly to this
    evidence. 
Definition ev_4''' : ev 4 :=
ev_SS 2 (ev_SS 0 ev_0).
ev_SS 2 (ev_SS 0 ev_0).
All these different ways of building the proof lead to exactly the
    same evidence being saved in the global environment. 
Print ev_4.
(* ===> ev_4 = ev_SS 2 (ev_SS 0 ev_0) : ev 4 *)
Print ev_4'.
(* ===> ev_4' = ev_SS 2 (ev_SS 0 ev_0) : ev 4 *)
Print ev_4''.
(* ===> ev_4'' = ev_SS 2 (ev_SS 0 ev_0) : ev 4 *)
Print ev_4'''.
(* ===> ev_4''' = ev_SS 2 (ev_SS 0 ev_0) : ev 4 *)
(* ===> ev_4 = ev_SS 2 (ev_SS 0 ev_0) : ev 4 *)
Print ev_4'.
(* ===> ev_4' = ev_SS 2 (ev_SS 0 ev_0) : ev 4 *)
Print ev_4''.
(* ===> ev_4'' = ev_SS 2 (ev_SS 0 ev_0) : ev 4 *)
Print ev_4'''.
(* ===> ev_4''' = ev_SS 2 (ev_SS 0 ev_0) : ev 4 *)
Theorem ev_8 : ev 8.
Proof.
(* FILL IN HERE *) Admitted.
Definition ev_8' : ev 8
(* REPLACE THIS LINE WITH ":= _your_definition_ ." *). Admitted.
☐ 
Proof.
(* FILL IN HERE *) Admitted.
Definition ev_8' : ev 8
(* REPLACE THIS LINE WITH ":= _your_definition_ ." *). Admitted.
Quantifiers, Implications, Functions
Theorem ev_plus4 : ∀ n, ev n → ev (4 + n).
Proof.
intros n H. simpl.
apply ev_SS.
apply ev_SS.
apply H.
Qed.
Proof.
intros n H. simpl.
apply ev_SS.
apply ev_SS.
apply H.
Qed.
What is the proof object corresponding to ev_plus4?
 
    We're looking for an expression whose type is ∀n, ev n →
    ev (4 + n) — that is, a function that takes two arguments (one
    number and a piece of evidence) and returns a piece of evidence!
 
    Here it is: 
Definition ev_plus4' : ∀ n, ev n → ev (4 + n) :=
fun (n : nat) ⇒ fun (H : ev n) ⇒
ev_SS (S (S n)) (ev_SS n H).
fun (n : nat) ⇒ fun (H : ev n) ⇒
ev_SS (S (S n)) (ev_SS n H).
Recall that fun n ⇒ blah means "the function that, given n,
    yields blah," and that Coq treats 4 + n and S (S (S (S n)))
    as synonyms. Another equivalent way to write this definition is: 
Definition ev_plus4'' (n : nat) (H : ev n)
: ev (4 + n) :=
ev_SS (S (S n)) (ev_SS n H).
Check ev_plus4''.
(* ===>
: forall n : nat, ev n -> ev (4 + n) *)
: ev (4 + n) :=
ev_SS (S (S n)) (ev_SS n H).
Check ev_plus4''.
(* ===>
: forall n : nat, ev n -> ev (4 + n) *)
When we view the proposition being proved by ev_plus4 as a
    function type, one interesting point becomes apparent: The second
    argument's type, ev n, mentions the value of the first
    argument, n.
 
    While such dependent types are not found in conventional
    programming languages, they can be useful in programming too, as
    the recent flurry of activity in the functional programming
    community demonstrates. 
 
 Notice that both implication (→) and quantification (∀)
    correspond to functions on evidence.  In fact, they are really the
    same thing: → is just a shorthand for a degenerate use of
    ∀where there is no dependency, i.e., no need to give a
    name to the type on the left-hand side of the arrow:
 
 
 For example, consider this proposition: 
           ∀ (x:nat), nat 
= ∀ (_:nat), nat
= nat → nat 
= ∀ (_:nat), nat
= nat → nat
Definition ev_plus2 : Prop :=
∀ n, ∀ (E : ev n), ev (n + 2).
∀ n, ∀ (E : ev n), ev (n + 2).
A proof term inhabiting this proposition would be a function
    with two arguments: a number n and some evidence E that n is
    even.  But the name E for this evidence is not used in the rest
    of the statement of ev_plus2, so it's a bit silly to bother
    making up a name for it.  We could write it like this instead,
    using the dummy identifier _ in place of a real name: 
Definition ev_plus2' : Prop :=
∀ n, ∀ (_ : ev n), ev (n + 2).
∀ n, ∀ (_ : ev n), ev (n + 2).
Or, equivalently, we can write it in more familiar notation: 
Definition ev_plus2'' : Prop :=
∀ n, ev n → ev (n + 2).
∀ n, ev n → ev (n + 2).
In general, "P → Q" is just syntactic sugar for
    "∀(_:P), Q". 
Programming with Tactics
Definition add1 : nat → nat.
intro n.
Show Proof.
apply S.
Show Proof.
apply n. Defined.
Print add1.
(* ==>
add1 = fun n : nat => S n
: nat -> nat
*)
Compute add1 2.
(* ==> 3 : nat *)
intro n.
Show Proof.
apply S.
Show Proof.
apply n. Defined.
Print add1.
(* ==>
add1 = fun n : nat => S n
: nat -> nat
*)
Compute add1 2.
(* ==> 3 : nat *)
Notice that we terminate the Definition with a . rather than
    with := followed by a term.  This tells Coq to enter proof
    scripting mode to build an object of type nat → nat.  Also, we
    terminate the proof with Defined rather than Qed; this makes
    the definition transparent so that it can be used in computation
    like a normally-defined function.  (Qed-defined objects are
    opaque during computation.)
 
    This feature is mainly useful for writing functions with dependent
    types, which we won't explore much further in this book.  But it
    does illustrate the uniformity and orthogonality of the basic
    ideas in Coq. 
Logical Connectives as Inductive Types
Module Props.
Conjunction
Module And.
Inductive and (P Q : Prop) : Prop :=
| conj : P → Q → and P Q.
End And.
Inductive and (P Q : Prop) : Prop :=
| conj : P → Q → and P Q.
End And.
Notice the similarity with the definition of the prod type,
    given in chapter Poly; the only difference is that prod takes
    Type arguments, whereas and takes Prop arguments. 
Print prod.
(* ===>
Inductive prod (X Y : Type) : Type :=
| pair : X -> Y -> X * Y. *)
(* ===>
Inductive prod (X Y : Type) : Type :=
| pair : X -> Y -> X * Y. *)
This should clarify why destruct and intros patterns can be
    used on a conjunctive hypothesis.  Case analysis allows us to
    consider all possible ways in which P ∧ Q was proved — here
    just one (the conj constructor).  Similarly, the split tactic
    actually works for any inductively defined proposition with only
    one constructor.  In particular, it works for and: 
Lemma and_comm : ∀ P Q : Prop, P ∧ Q ↔ Q ∧ P.
Proof.
intros P Q. split.
- intros [HP HQ]. split.
+ apply HQ.
+ apply HP.
- intros [HP HQ]. split.
+ apply HQ.
+ apply HP.
Qed.
Proof.
intros P Q. split.
- intros [HP HQ]. split.
+ apply HQ.
+ apply HP.
- intros [HP HQ]. split.
+ apply HQ.
+ apply HP.
Qed.
This shows why the inductive definition of and can be
    manipulated by tactics as we've been doing.  We can also use it to
    build proofs directly, using pattern-matching.  For instance: 
Definition and_comm'_aux P Q (H : P ∧ Q) :=
match H with
| conj HP HQ ⇒ conj HQ HP
end.
Definition and_comm' P Q : P ∧ Q ↔ Q ∧ P :=
conj (and_comm'_aux P Q) (and_comm'_aux Q P).
match H with
| conj HP HQ ⇒ conj HQ HP
end.
Definition and_comm' P Q : P ∧ Q ↔ Q ∧ P :=
conj (and_comm'_aux P Q) (and_comm'_aux Q P).
Definition conj_fact : ∀ P Q R, P ∧ Q → Q ∧ R → P ∧ R
(* REPLACE THIS LINE WITH ":= _your_definition_ ." *). Admitted.
☐ 
(* REPLACE THIS LINE WITH ":= _your_definition_ ." *). Admitted.
Disjunction
Module Or.
Inductive or (P Q : Prop) : Prop :=
| or_introl : P → or P Q
| or_intror : Q → or P Q.
End Or.
Inductive or (P Q : Prop) : Prop :=
| or_introl : P → or P Q
| or_intror : Q → or P Q.
End Or.
This declaration explains the behavior of the destruct tactic on
    a disjunctive hypothesis, since the generated subgoals match the
    shape of the or_introl and or_intror constructors.
 
    Once again, we can also directly write proof objects for theorems
    involving or, without resorting to tactics. 
 
Exercise: 2 stars (or_commut'')
Try to write down an explicit proof object for or_commut (without using Print to peek at the ones we already defined!).
Definition or_comm : ∀ P Q, P ∨ Q → Q ∨ P
(* REPLACE THIS LINE WITH ":= _your_definition_ ." *). Admitted.
☐ 
(* REPLACE THIS LINE WITH ":= _your_definition_ ." *). Admitted.
Existential Quantification
Module Ex.
Inductive ex {A : Type} (P : A → Prop) : Prop :=
| ex_intro : ∀ x : A, P x → ex P.
End Ex.
Inductive ex {A : Type} (P : A → Prop) : Prop :=
| ex_intro : ∀ x : A, P x → ex P.
End Ex.
This may benefit from a little unpacking.  The core definition is
    for a type former ex that can be used to build propositions of
    the form ex P, where P itself is a function from witness
    values in the type A to propositions.  The ex_intro
    constructor then offers a way of constructing evidence for ex P,
    given a witness x and a proof of P x. 
 
 The more familiar form ∃x, P x desugars to an expression
    involving ex: 
Check ex (fun n ⇒ ev n).
(* ===> exists n : nat, ev n
: Prop *)
(* ===> exists n : nat, ev n
: Prop *)
Here's how to define an explicit proof object involving ex: 
Definition some_nat_is_even : ∃ n, ev n :=
ex_intro ev 4 (ev_SS 2 (ev_SS 0 ev_0)).
ex_intro ev 4 (ev_SS 2 (ev_SS 0 ev_0)).
Definition ex_ev_Sn : ex (fun n ⇒ ev (S n))
(* REPLACE THIS LINE WITH ":= _your_definition_ ." *). Admitted.
☐ 
(* REPLACE THIS LINE WITH ":= _your_definition_ ." *). Admitted.
Inductive True : Prop :=
| I : True.
| I : True.
It has one constructor (so every proof of True is the same, so
    being given a proof of True is not informative.) 
 
 False is equally simple — indeed, so simple it may look
    syntactically wrong at first glance! 
Inductive False : Prop :=.
That is, False is an inductive type with no constructors —
    i.e., no way to build evidence for it. 
End Props.
Equality
Module MyEquality.
Inductive eq {X:Type} : X → X → Prop :=
| eq_refl : ∀ x, eq x x.
Notation "x == y" := (eq x y)
(at level 70, no associativity)
: type_scope.
Inductive eq {X:Type} : X → X → Prop :=
| eq_refl : ∀ x, eq x x.
Notation "x == y" := (eq x y)
(at level 70, no associativity)
: type_scope.
The way to think about this definition is that, given a set X,
    it defines a family of propositions "x is equal to y,"
    indexed by pairs of values (x and y) from X.  There is just
    one way of constructing evidence for each member of this family:
    applying the constructor eq_refl to a type X and a value x :
    X yields evidence that x is equal to x. 
 
 We can use eq_refl to construct evidence that, for example, 2 =
    2.  Can we also use it to construct evidence that 1 + 1 = 2?
    Yes, we can.  Indeed, it is the very same piece of evidence!
 
    The reason is that Coq treats as "the same" any two terms that are
    convertible according to a simple set of computation rules.
 
    These rules, which are similar to those used by Compute, include
    evaluation of function application, inlining of definitions, and
    simplification of matches.  
Lemma four: 2 + 2 == 1 + 3.
Proof.
apply eq_refl.
Qed.
Proof.
apply eq_refl.
Qed.
The reflexivity tactic that we have used to prove equalities up
    to now is essentially just short-hand for apply eq_refl.
 
    In tactic-based proofs of equality, the conversion rules are
    normally hidden in uses of simpl (either explicit or implicit in
    other tactics such as reflexivity).
 
    But you can see them directly at work in the following explicit
    proof objects: 
Definition four' : 2 + 2 == 1 + 3 :=
eq_refl 4.
Definition singleton : ∀ (X:Type) (x:X), []++[x] == x::[] :=
fun (X:Type) (x:X) ⇒ eq_refl [x].
eq_refl 4.
Definition singleton : ∀ (X:Type) (x:X), []++[x] == x::[] :=
fun (X:Type) (x:X) ⇒ eq_refl [x].
Exercise: 2 stars (equality__leibniz_equality)
The inductive definition of equality implies Leibniz equality: what we mean when we say "x and y are equal" is that every property on P that is true of x is also true of y.
Lemma equality__leibniz_equality : ∀ (X : Type) (x y: X),
x == y → ∀ P:X→Prop, P x → P y.
Proof.
(* FILL IN HERE *) Admitted.
☐ 
x == y → ∀ P:X→Prop, P x → P y.
Proof.
(* FILL IN HERE *) Admitted.
Exercise: 5 stars, optional (leibniz_equality__equality)
Show that, in fact, the inductive definition of equality is equivalent to Leibniz equality:
Lemma leibniz_equality__equality : ∀ (X : Type) (x y: X),
(∀ P:X→Prop, P x → P y) → x == y.
Proof.
(* FILL IN HERE *) Admitted.
☐ 
(∀ P:X→Prop, P x → P y) → x == y.
Proof.
(* FILL IN HERE *) Admitted.
End MyEquality.
Inversion, Again
-  takes a hypothesis H whose type P is inductively defined,
      and
-  for each constructor C in P's definition,
-  generates a new subgoal in which we assume H was
        built with C,
-  adds the arguments (premises) of C to the context of
        the subgoal as extra hypotheses,
-  matches the conclusion (result type) of C against the
        current goal and calculates a set of equalities that must
        hold in order for C to be applicable,
-  adds these equalities to the context (and, for convenience,
        rewrites them in the goal), and
- if the equalities are not satisfiable (e.g., they involve things like S n = O), immediately solves the subgoal.
 
-  generates a new subgoal in which we assume H was
        built with C,
