1 00:00:00,000 --> 00:00:03,400 Hello everyone. So in 
this example, we're going to 2 00:00:03,400 --> 00:00:07,400 count the number of even divisors of the number 1280. 3 00:00:07,400 --> 00:00:09,400 Now when you see the
word “divisors”, 4 00:00:09,400 --> 00:00:14,400 you should be thinking maybe 
using divisors from prime factorization. 5 00:00:14,400 --> 00:00:15,866 so DFPF. 6 00:00:15,866 --> 00:00:19,400 But in order to do that, you
need to prime factor 1280. 7 00:00:19,400 --> 00:00:23,400 So first, we factor 1280. 8 00:00:23,400 --> 00:00:23,900 9 00:00:23,900 --> 00:00:25,900 Well so here we have 1280, 10 00:00:25,900 --> 00:00:27,900 now I notice immediately
that 4 is a factor. 11 00:00:27,900 --> 00:00:31,900 Right? So 4 goes into 12 three times. 12 00:00:31,900 --> 00:00:33,900 No remainder. Then 4 
goes into 8 twice, 13 00:00:33,900 --> 00:00:35,900 and 4 goes into 0 zero times. 14 00:00:35,900 --> 00:00:37,900 So if we factor out the 4
we have 4 times 320. 15 00:00:37,900 --> 00:00:41,300 320 is easy to see, 
that's 32 times 10. 16 00:00:41,300 --> 00:00:43,900 and all of these numbers are small 
enough that I can prime factor them. 17 00:00:43,900 --> 00:00:46,166 2 squared, times 2 to the 5,
times 2, times 5, 18 00:00:46,166 --> 00:00:48,300 that's 2 to
the 8 times 5. 19 00:00:48,300 --> 00:00:51,800 Now DFPF, so divisors from prime factorization, 20 00:00:51,800 --> 00:00:54,433 says that the divisors of 
this number of the form, 21 00:00:54,433 --> 00:00:57,666 “2 to the a times
 5 to the b” 22 00:00:57,666 --> 00:00:59,666 with a being a number
between 0 and 8, 23 00:00:59,666 --> 00:01:02,166 and b being a number 
between 0 and 1. 24 00:01:02,166 --> 00:01:05,666 This gives us all the divisors of 1280. 25 00:01:05,666 --> 00:01:10,166 However, to get just the even factors,
we need at least one copy of 2. 26 00:01:10,166 --> 00:01:14,666 And hence, we will increase 
the lower bound on a to 1, 27 00:01:14,666 --> 00:01:17,400 and thus, 1 is less than or equal to a which is less than or equal to 8. 28 00:01:17,400 --> 00:01:21,233 So, what are the possible
values now for a? 29 00:01:21,233 --> 00:01:25,233 Well a is now between 1 and 8, and so thus, we have 7 plus 1 possible factors 30 00:01:25,233 --> 00:01:27,566 (the plus 1 is because we 
count both endpoints, so 31 00:01:27,566 --> 00:01:30,233 we take 8 minus 1 that's 7 plus 1 for both endpoints), 32 00:01:30,233 --> 00:01:34,600 and that gives us the total number of possibilities for the power of 2. 33 00:01:34,600 --> 00:01:37,633 And we're going to take 1
plus 1 which is equal to 2, 34 00:01:37,633 --> 00:01:40,600 and that's the total possibilities
for the factors of 5, right? 35 00:01:40,600 --> 00:01:42,700 It's either 5 to the 
0, or 5 to the 1. 36 00:01:42,700 --> 00:01:45,900 It's 1 plus 1, again the difference 
plus 1 for the fact that we count both
endpoints. 37 00:01:45,900 --> 00:01:49,900 That's 8 times 2 and that equals 
16 possible even divisors of 1280. 38 00:01:49,900 --> 00:01:53,900 So you might want to practice writing 39 00:01:53,900 --> 00:01:56,600 down the 16 possibilities 
just to get some extra 40 00:01:56,600 --> 00:01:59,333 divisor from prime 
factorization help. 41 00:01:59,333 --> 00:02:02,366 So thank you very much, and 
hopefully this gives you an idea of 42 00:02:02,366 --> 00:02:05,900 how to use DFPF to compute
the divisors of a number. 43 00:02:05,900 --> 00:02:06,400