1 00:00:00,100 --> 00:00:04,400 Hello everyone, and welcome to this week's Carmen's Core Concepts. 2 00:00:04,400 --> 00:00:07,000 This is week 2, my 
name is Carmen Bruni, 3 00:00:07,000 --> 00:00:09,300 and this week we're 
gonna talk about some 4 00:00:09,300 --> 00:00:11,800 of the key concepts that we 
did in Math 135 in week 2. 5 00:00:11,800 --> 00:00:14,633 Again, I want to remind you that this isn't a substitute for lectures 6 00:00:14,633 --> 00:00:16,900 in any way, shape, or form. I'll 
be going way too quickly 7 00:00:16,900 --> 00:00:18,900 for this to be a 
substitute for lectures, 8 00:00:18,900 --> 00:00:22,433 but what this is supposed to do is it's supposed 
to reinforce the key ideas of the week 9 00:00:22,433 --> 00:00:24,266 to give you an idea 
of what we did 10 00:00:24,266 --> 00:00:27,000 and to be used in conjunction 
with other tools, 11 00:00:27,000 --> 00:00:30,333 like going to lectures, like practicing the problems, etc etc. 12 00:00:30,333 --> 00:00:30,366 13 00:00:30,366 --> 00:00:32,666 So let's start with 
divisibility theorems. 14 00:00:32,666 --> 00:00:35,466 So last week we finished off 
with Bounds By Divisibility, 15 00:00:35,466 --> 00:00:37,533 this week we'll start with it and 
talk about a couple of others. 16 00:00:37,533 --> 00:00:38,866 So let a, b, c 
be integers, 17 00:00:38,866 --> 00:00:40,833 recall that Bounds By Divisibility states that 18 00:00:40,833 --> 00:00:42,433 "if a divides b and b is non-zero, 19 00:00:42,433 --> 00:00:45,300 then the magnitude of a is less than 
or equal to the magnitude of b." 20 00:00:45,300 --> 00:00:48,133 So it gives us a bound 
on the size of a and b. 21 00:00:48,133 --> 00:00:49,866 So if a and b are always positive, then 22 00:00:49,866 --> 00:00:52,633 a must be less than or equal to b, if it divides... 23 00:00:52,633 --> 00:00:54,966 if a divides b,
for example. 24 00:00:54,966 --> 00:00:57,466 Transitivity of Divisibility, 
so we call this TD. 25 00:00:57,466 --> 00:01:01,900 Transitivity itself is a very important 
mathematical concept. It's 26 00:01:01,900 --> 00:01:05,500 one of the conditions to be an equivalence relation, for example. 27 00:01:05,500 --> 00:01:07,400 So we'll see 
it again later. 28 00:01:07,400 --> 00:01:09,233 What do we have here? We have 29 00:01:09,233 --> 00:01:12,700 a divides b and b divides c and 
that implies that a divides c, 30 00:01:12,700 --> 00:01:15,000 so the transitivity part is if 
the middle thing is the same, 31 00:01:15,000 --> 00:01:17,366 so in this case the 
b on either side, 32 00:01:17,366 --> 00:01:20,066 and a divides b and b divides c, then a must divide c. 33 00:01:20,066 --> 00:01:22,666 This can be…you can change 
divisibility with, let's say "equals", 34 00:01:22,666 --> 00:01:24,433 or other operators 
that you know. 35 00:01:24,433 --> 00:01:26,266 So many things 
are transitive. 36 00:01:26,266 --> 00:01:29,933 Divisibility of Integer Combinations, 
one of the 37 00:01:29,933 --> 00:01:32,666 most used theorems 
of this course. 38 00:01:32,666 --> 00:01:34,633 If a divides b 
and a divide c, 39 00:01:34,633 --> 00:01:37,866 then for all x and y 
inside the integers, 40 00:01:37,866 --> 00:01:39,866 a divides b x plus c [y]. 41 00:01:39,866 --> 00:01:42,766 So we'll talk about “for all” a little bit more in depth later, but 42 00:01:42,766 --> 00:01:45,566 I just want to use this symbol here 
just to show that you can write 43 00:01:45,566 --> 00:01:47,433 DIC using just symbols. 44 00:01:47,433 --> 00:01:51,100 The proof of DIC it’s, again, one of these 
“follow your nose” type of proofs I like to say. 45 00:01:51,100 --> 00:01:53,300 Assume the hypothesis, 
and then it kind of just 46 00:01:53,300 --> 00:01:55,933 gradually leads you 
towards the conclusion. 47 00:01:55,933 --> 00:01:58,733 At this point in the course, we 
really don't have any tools so 48 00:01:58,733 --> 00:02:01,166 if all you get is a divides 
b and a divides c, 49 00:02:01,166 --> 00:02:03,233 you probably want 
to use the definition. 50 00:02:03,233 --> 00:02:04,266 51 00:02:04,266 --> 00:02:08,600 Using the definition gives you integers m and 
n such that a m equals b and a n equals c, 52 00:02:08,600 --> 00:02:11,366 and then for any integers x and y, we have that 53 00:02:11,366 --> 00:02:14,600 b x plus c y is equal to 
a times some integer, 54 00:02:14,600 --> 00:02:17,300 and hence, a divides 
b x plus c y. 55 00:02:17,300 --> 00:02:19,166 So the proof, again, is a “follow 
your nose” kind of proof. 56 00:02:19,166 --> 00:02:20,800 It's very short, 
very sweet, 57 00:02:20,800 --> 00:02:25,300 but this property here, this theorem, has a lot of applications. 58 00:02:25,300 --> 00:02:27,200 Let's see an 
example of them. 59 00:02:27,200 --> 00:02:28,066 60 00:02:28,066 --> 00:02:30,033 Here's just one example 
of applying it, 61 00:02:30,033 --> 00:02:33,300 so if 5 divides a plus 2b 
and 5 divides 2a plus b, 62 00:02:33,300 --> 00:02:36,366 then 5 divides… 
well if I take 63 00:02:36,366 --> 00:02:38,566 2 times the 
first term, 64 00:02:38,566 --> 00:02:42,333 and and add negative 1 
times the second term, 65 00:02:42,333 --> 00:02:44,600 then it divides that. 
Well what is that? 66 00:02:44,600 --> 00:02:47,966 Well it's 2a plus 4b 
minus 2a minus b, 67 00:02:47,966 --> 00:02:50,933 the two a’s are gonna cancel and 
you’re gonna be left with 3b. 68 00:02:50,933 --> 00:02:54,200 So this shows you a way that you can 
use Divisibility of Integer Combinations 69 00:02:54,200 --> 00:02:57,133 to find integer combinations 
to get things like… 70 00:02:57,133 --> 00:02:59,900 so to get rid of a variable, for 
example, so here we got rid of a, 71 00:02:59,900 --> 00:03:02,733 you can use them prove 
all sorts of things. 72 00:03:02,733 --> 00:03:05,700 Proving that big numbers are divisible if you know that smaller numbers are, 73 00:03:05,700 --> 00:03:07,700 so you can combine them 
to make bigger numbers 74 00:03:07,700 --> 00:03:09,300 that are divisible by 
certain numbers. 75 00:03:09,300 --> 00:03:11,300 Lots of interesting 
applications of DIC. 76 00:03:11,300 --> 00:03:13,566 Again, we're gonna see this throughout the course, 77 00:03:13,566 --> 00:03:16,100 so it is worth its own slide 
to give an example. 78 00:03:16,100 --> 00:03:18,800 Very short, but it 
is a core concept 79 00:03:18,800 --> 00:03:23,766 and you really should try to 
understand DIC in its fullness. 80 00:03:23,766 --> 00:03:25,300 81 00:03:25,300 --> 00:03:28,466 Converses, so next
week especially 82 00:03:28,466 --> 00:03:31,033 we're going to see a lot of words 
that begin with the letter C, 83 00:03:31,033 --> 00:03:33,466 and it's very easy to get 
them confused, so 84 00:03:33,466 --> 00:03:35,833 now is a good time that 
we just have this one 85 00:03:35,833 --> 00:03:39,700 to put it in your memory banks and make 
sure that you have it down solid. 86 00:03:39,700 --> 00:03:41,433 Let A and B 
be statements. 87 00:03:41,433 --> 00:03:44,700 the converse of A implies 
B is B implies A. 88 00:03:44,700 --> 00:03:46,900 So hypothesis implies 
conclusion, 89 00:03:46,900 --> 00:03:49,300 the converse is conclusion 
implies hypothesis. 90 00:03:49,300 --> 00:03:51,566 A very simple definition. 91 00:03:51,566 --> 00:03:54,500 Converses are useful 
in mathematics. 92 00:03:54,500 --> 00:03:56,766 If you prove an implication 
and you prove its converse, 93 00:03:56,766 --> 00:03:59,766 that's much stronger than just proving an implication itself. 94 00:03:59,766 --> 00:04:03,433 It somehow gives you a 
classification-type theorem, 95 00:04:03,433 --> 00:04:06,366 which is a lot stronger than just an implication. 96 00:04:06,366 --> 00:04:09,300 So as an example, the converse 
of Bounds By Divisibility 97 00:04:09,300 --> 00:04:10,966 is given by, 98 00:04:10,966 --> 00:04:13,300 “if the absolute value of a is less than 
or equal to the absolute value of b, 99 00:04:13,300 --> 00:04:17,866 then a divides b and 
b does not equal 0." 100 00:04:17,866 --> 00:04:21,300 Notice that 
this is false. 101 00:04:21,300 --> 00:04:24,166 There's many counter 
examples of this, 102 00:04:24,166 --> 00:04:27,466 so I mean, just take a equals 6 
and b equals 7, for example. 103 00:04:27,466 --> 00:04:30,833 6 is less than 7 but clearly 
6 does not divide 7. 104 00:04:30,833 --> 00:04:33,300 105 00:04:33,300 --> 00:04:37,300 There are plenty of examples 
where this can go awry. 106 00:04:37,300 --> 00:04:39,300 107 00:04:39,300 --> 00:04:41,666 Okay, that's all I really want to say about converses. 108 00:04:41,666 --> 00:04:45,600 But we can use converses in the 
next topic which is “if and only if” 109 00:04:45,600 --> 00:04:46,900 statements. 110 00:04:46,900 --> 00:04:48,866 So again, let A and 
B be statements. 111 00:04:48,866 --> 00:04:51,100 we defined “if and only 
if”… so A if and only if B 112 00:04:51,100 --> 00:04:53,000 we defined it 
by a truth table. 113 00:04:53,000 --> 00:04:56,300 Here we said A if and only if B is true 114 00:04:56,300 --> 00:05:00,233 if and only if both A and B are true or 
false, so they share the same value. 115 00:05:00,233 --> 00:05:03,133 So if A and B share the 
same truth or false value, 116 00:05:03,133 --> 00:05:07,700 then we say that A if and only if B 
is true, and otherwise it's false. 117 00:05:07,700 --> 00:05:09,066 118 00:05:09,066 --> 00:05:11,166 So how do we prove 'if and 
only if' questions in practice? 119 00:05:11,166 --> 00:05:13,066 This exercise is what actually shows it. 120 00:05:13,066 --> 00:05:15,166 I'm not going to prove it, I 
didn’t prove it in class either, 121 00:05:15,166 --> 00:05:17,733 “Show that A if and only if B is logically equivalent to 122 00:05:17,733 --> 00:05:20,266 A implies B ‘and’ B implies A.” 123 00:05:20,266 --> 00:05:22,066 That's something I'll 
leave as an exercise. 124 00:05:22,066 --> 00:05:24,133 But this gives you an idea of how to prove it. 125 00:05:24,133 --> 00:05:27,100 Well you prove the normal 
thing, you prove 126 00:05:27,100 --> 00:05:29,000 the implication 
A implies B, 127 00:05:29,000 --> 00:05:30,933 and then you prove 
its converse. 128 00:05:30,933 --> 00:05:33,033 So if an implication and its 
converse are true, then 129 00:05:33,033 --> 00:05:35,566 the statement is an ‘if 
and only if’ statement. 130 00:05:35,566 --> 00:05:39,333 We'll see a practical example 
of ‘if and only if’s 131 00:05:39,333 --> 00:05:42,766 when we deal with sets afterwards. 
I wanted to say that to 132 00:05:42,766 --> 00:05:46,400 accumulate everything; 
to give a nice 133 00:05:46,400 --> 00:05:48,166 bridge between 
the two topics. 134 00:05:48,166 --> 00:05:50,966 But that basically covers the end 
of the first lecture of the week.