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An Inequality for Macaulay Functions

Bernardo M. Ábrego and Silvia Fernández-Merchant
Department of Mathematics
California State University, Northridge
18111 Nordhoff Street
Northridge, CA 91330
USA
mailto:bernardo.abrego@csun.edubernardo.abrego@csun.edu
mailto:silvia.fernandez@csun.edusilvia.fernandez@csun.edu

Bernardo Llano
Departamento de Matemáticas
Universidad Autónoma Metropolitana, Iztapalapa
San Rafael Atlixco 186
Colonia Vicentina, 09340, México, D.F.
México
mailto:llano@xanum.uam.mxllano@xanum.uam.mx

in

Abstract:

Given integers $ k\geq1$ and $ n\geq0$, there is a unique way of writing $ n$ as $ n=\binom{n_{k}}{k}+\binom{n_{k-1}}{k-1}+\cdots+\binom{n_{1}}{1}$ so that $ 0\leq n_{1}<\cdots<n_{k-1}<n_{k}$. Using this representation, the k $ ^{\text{th}}$ Macaulay function of $ n$ is defined as $ \partial^{k}( n)
=\binom{n_{k}-1}{k-1}+\binom{n_{k-1}-1}{k-2}+\cdots+\binom{n_{1}-1}
{0}.$ We show that if $ a\geq0$ and $ a<\partial^{k+1}(n) $, then $ \partial^{k}(a) +\partial^{k+1}( n-a) \geq
\partial^{k+1}(n)$. As a corollary, we obtain a short proof of Macaulay's Theorem. Other previously known results are obtained as direct consequences.



Jeffrey Shallit 2011-09-05